Calculating Entropy Change in a Thermal Conduction System

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SUMMARY

The discussion focuses on calculating the total change in entropy for a thermal conduction system involving a metal wire in contact with two heat reservoirs at temperatures of 752 K and 345 K. The correct approach utilizes the equation dS = dQ / T, leading to the calculation of entropy change as -1096 J / 752 K + 1096 J / 345 K, resulting in a total change of 1.72 J/K. Participants confirm the validity of this method and the accuracy of the final answer, emphasizing the straightforward nature of the problem despite initial doubts.

PREREQUISITES
  • Understanding of thermodynamics principles, specifically entropy.
  • Familiarity with the equation dS = dQ / T.
  • Knowledge of heat transfer concepts in thermal conduction.
  • Basic proficiency in algebra for solving equations.
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  • Study the laws of thermodynamics, particularly the second law.
  • Learn about heat transfer mechanisms in different materials.
  • Explore advanced entropy calculations in multi-reservoir systems.
  • Investigate real-world applications of entropy in engineering and physics.
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Students studying thermodynamics, educators teaching heat transfer concepts, and professionals in engineering fields focused on thermal systems.

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Homework Statement


Each end of a metal wire is in thermal contact with a different heat reservoir.
Reservoir 1 is at a temperature of 752 K, and reservoir 2 is at a temperature of
345 K. Compute the total change in entropy that occurs from the conduction of
1096 J of heat through the wire.


Homework Equations


dS = dQ / T


The Attempt at a Solution


I'm really unsure how to solve this question. Would I do something like this:

-1096/752 + 1096/345 =
-1.457 + 3.177 = 1.72 J/K

Or am I totally off base on this one?
 
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bpaterni said:

The Attempt at a Solution


I'm really unsure how to solve this question. Would I do something like this:

-1096/752 + 1096/345 =
-1.457 + 3.177 = 1.72 J/K
I am not sure why you are unsure. You have the right equation and you have the right answer.

AM
 
Wow, okay... Thanks for the reassurance then! :)

The question has a point value of 6 points out of a 25 point homework assignment, so I thought there might be more to it than that, but apparently I thought wrong.
 

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