Calculating Equilibrium Height of 2 Cylinders

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SUMMARY

The discussion focuses on calculating the equilibrium height of two connected cylinders, one open to the atmosphere and the other subjected to a downward force of 702.9N. The key principle involves equating the pressures on both sides, which can be expressed using the formula P(kPa) = density (1 for water) * gravity (9.8 m/s²) * delta height (meters). Additionally, the diameter of the cylinder with the weight is essential for determining the pressure exerted on that side, influencing the height of the fluid in the other cylinder.

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JSBeckton
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I'm trying to remember how to calculate the equlibrium height of a system of 2 cylinders connected by a tube at the bottom with the smaller cylinder open to the atmosphere and 702.9N pressing down on the other side.

I believe it has to do with the pressure being equal on both sides or potential energy being equal, its been a while since I did these, can anyine refresh my memory? Thanks.
 
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For U tube, with 1 end open to atmosphere, the unknown P(kPa)=density (1 for water) * gravity (9.8) * delta Heighth (meters).

I think you would need the diameter of the cylinder with the wieght on it to calculate the pressure on that side. The other side would rise up until the delta H is equal to the pressure in the cylinder.
 
thanks for your help.
 

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