Calculating Escape Velocity of the Moon

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The gravitational acceleration of the Moon is 1.6 m/s², which is essential for calculating its escape velocity. The formula used for this calculation is v = √(2GM/r), where G is the gravitational constant and r is the radius of the Moon. Participants in the discussion express confusion about the problem, particularly regarding the need for the Moon's radius to complete the calculation. The radius of the Moon is typically known and can be used alongside the given gravitational acceleration to find the escape velocity. Understanding these parameters is crucial for solving the problem effectively.
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Homework Statement


The gravitational acceleration of the moon is 1.6 m/s^-2. Estimate its escape velocity and explain how you did this?


Homework Equations



v= square roots(2GM/r)

The Attempt at a Solution


I have absolutely no idea how to do this question at all
 
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Weren't you given the radius of the moon too?
 
Thread 'Correct statement about size of wire to produce larger extension'

Thread 'Correct statement about size of wire to produce larger extension'

The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...
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