Calculating expended energy in a battery

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To calculate the energy expended by a 42 V battery to charge capacitors in parallel, first determine the total capacitance by summing the individual capacitances of 3.62x10^-6 F and 6.11x10^-6 F. The total capacitance is 9.73x10^-6 F. The energy stored in a capacitor can be found using the formula U = 1/2 CV^2, where C is the total capacitance and V is the voltage. Applying this formula will yield the energy required from the battery. Understanding these calculations is essential for accurately determining the energy expenditure.
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Homework Statement


How much energy must a 42 V battery expend to fully charge a 3.62x10-6 F and a 6.11x10-6 F capacitor when they are placed in parallel?


Homework Equations



capacitor in parallel therefore total capacitance is the sum...

The Attempt at a Solution


I thought that you could use U=Vq but apparently you can't because I was getting the wrong answers.. this is the same question that I tried to do before but with different values. HELP :)
 
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When in parallel, what is the total capacitance?

How do you find the energy stored in a capacitor?
 
Thank you so much!
 

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