Calculating Exterior Surface Area of Prism | Complex Maths

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Discussion Overview

The discussion revolves around calculating the exterior surface area of a prism, specifically focusing on a triangular prism and a cylindrical component. Participants explore various methods for determining the surface area, including breaking the surface into smaller pieces and using geometric formulas. The scope includes mathematical reasoning and conceptual clarification related to surface area calculations.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Homework-related

Main Points Raised

  • One participant seeks the formula for the exterior surface area of a prism and mentions known formulas for triangular prisms and cylinders.
  • Another suggests breaking the surface into smaller pieces to calculate the area of each piece individually and then summing them up.
  • It is proposed that the outer surface area can also be found by multiplying the perimeter of the base by the height, excluding the top and bottom pieces.
  • A participant describes the surface as consisting of rectangular pieces, cylindrical sections, right triangles, and semi-circles, and suggests using the Pythagorean theorem to find dimensions.
  • Clarification is sought on the participant's understanding of various geometric calculations, including areas of rectangles, right triangles, circles, and their respective perimeters.
  • One participant explains that the area of the curving surface can be conceptualized as a rectangle when unbent, with height and width derived from the dimensions of the circular base.
  • There is a reiteration that the term "perimeter" may be confusing, clarifying that it refers to the circumference of the circle.

Areas of Agreement / Disagreement

Participants express varying levels of understanding regarding the methods for calculating surface area, and there is no consensus on a single approach. Some methods are proposed, but the discussion remains open-ended with multiple perspectives on how to proceed.

Contextual Notes

Participants have differing levels of familiarity with the mathematical concepts involved, leading to requests for clarification on specific calculations and methods. The discussion does not resolve the best approach to calculating the surface area.

Who May Find This Useful

Students studying geometry, particularly those focused on surface area calculations in prisms and cylinders, as well as individuals seeking clarification on geometric principles and methods.

risphysics
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I'm a new student to complex maths & I'm after the formula to calculate the exterior surface area of the prism - see attached diagram.
I know formula for a surface area of triangular prism = ab + ph and cylinder = 2pir^2 + 2 pi rh. Don't know where/how to apply formula to half of these.
Thanks for your assistance.
 

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There are a couple ways to do this. One is to break the surface into a bunch of pieces, like in this image:
http://img371.imageshack.us/img371/3480/areapeicesij5.png

and then find the surface area of each of the peices individually and add them up (Have you learned how to do this yet?)

Another way to find the outer surface (excluding the top and bottom peices) is to multiply the perimeter of the base by the height.

Both ways will give the same result.
 
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No I haven't learned the method of breaking it up into pieces. Could you elaborate further pls.
I'm studying Residential Drafting via correspondece, so unfortunately I do not have a teacher to refer to. Thanks again.
 
"Breaking it into pieces" is really just looking at it.

I see the surface as having two rectangular pieces, one long cylindrical piece, and, on the ends, two right triangles and two semi-circles. Find the areas of each of those and add. You are given the length of the long part and the diameter (so twice the radius) of the circular pieces. To find the width of the rectangular pieces, use the Pythagorean theorem on the right triangles.

The area of the surface of a semicircular cylinder is the circumference of the semicircle multiplied by the length of the cylinder. Surely you know how to find the area of a semi-circle, rectangle, and triangle.
 
Can you please tell me which of the things in this list you know how to do, and which you don't, so I can make a better explanation.
1) Find the area of a rectangle.
2) Find the area of a right triangle (triangle where one of the angles is 90 degrees).
3) Find the length of one side of a right triangle if you know the other 2 sides.
4) Find the area of a circle.
5) Find the perimeter of a circle.

Thanks.
 
maze said:
Can you please tell me which of the things in this list you know how to do, and which you don't, so I can make a better explanation.
1) Find the area of a rectangle.
2) Find the area of a right triangle (triangle where one of the angles is 90 degrees).
3) Find the length of one side of a right triangle if you know the other 2 sides.
4) Find the area of a circle.
5) Find the perimeter of a circle.

Thanks.
(1) a = bxh
(2) a = 1/2 bxh
(3) AB^2 = AB^2 + (AB)^2
(4) = nr^2 (circ / diam)
(5) Not 100% sure on finding perimter of cirlce

Thanks for taking the time Maze.
 
If you look at all the surfaces on there from the picture in my previous post, parts 1,2,4,5,6, and 7 are triangles, rectangles, and half-circles, which you know how to find the area of, so I'm not going to talk about those.

That leaves only a single piece left, piece 3, the curving one. Now, this brings up the question: what does it mean to find the area of a curving sheet? It means, if you were going to create the curving part by bending a piece of paper, how much paper would you need?

You can try this with a real piece of paper, or imagine it in your mind, but if you un-bend piece 3 and make it flat, it will be a rectangle. It's height is already given, and the width is one half of the perimeter of the circle.

(By the way, perhaps the word perimeter is confusing you. When I say perimeter, I just mean the circumference of the circle)

The perimeter of the whole circle is 2*pi*r, so the perimeter of one half the circle is pi*r.
 
maze said:
If you look at all the surfaces on there from the picture in my previous post, parts 1,2,4,5,6, and 7 are triangles, rectangles, and half-circles, which you know how to find the area of, so I'm not going to talk about those.

That leaves only a single piece left, piece 3, the curving one. Now, this brings up the question: what does it mean to find the area of a curving sheet? It means, if you were going to create the curving part by bending a piece of paper, how much paper would you need?

You can try this with a real piece of paper, or imagine it in your mind, but if you un-bend piece 3 and make it flat, it will be a rectangle. It's height is already given, and the width is one half of the perimeter of the circle.

(By the way, perhaps the word perimeter is confusing you. When I say perimeter, I just mean the circumference of the circle)

The perimeter of the whole circle is 2*pi*r, so the perimeter of one half the circle is pi*r.
Thanks so much ... you have simplified it for me to understand now.
 

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