Calculating Fill Time for a Cylindrical Grow-Out Tank | Water Flow Question

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SUMMARY

The discussion focuses on calculating the fill time for a cylindrical grow-out tank with a height of 2 meters and a diameter of 8 meters, accounting for a 10% freeboard. The tank's total volume is approximately 90.48 cubic meters. The inlet pump delivers water at a rate of 25 liters per minute, which converts to 0.025 cubic meters per minute or 1.5 cubic meters per second. The correct approach to determine fill time is to divide the tank volume by the delivery rate, not to use the delivery rate as a height variable.

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majin
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I am stuck on questions like this can anyone help
How long would it take to fill a cylindrical grow-out tank (2m high, 8m diameter, 10% freeboard) from an inlet pump delivering 25 litres of water every minute through a 25mm pipe that has 4 spray outlets?

first of all I know that the 4 spray outlets are irrelevant to the quetion and are a decoy. as well as this i know that the pipe is cylindrical

tank volume with freeBoard =90.47786842
25 L/min converts into 0.025 m3/min
to get that into m3 per sec(delivery rate) I times it by 60=1.5m3/sec

So to get the answer do I divide the delivery rate(1.5) into the tank volume i.e(90/1.5) OR do I use the delivery rate as a height(h) variable and work out volume of pipe i.e(pi*h*r*r)and then divide the volume of the pipe into the tank volume i.e(vt/vp) to get the amount in secs? any help will be greatly appreciated
 
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That's one odd pump, delivering 0.025 m3/min but 1.5m3/sec.

You can't use the delivery rate as a height variable because height is measured in metres and delivery rate is m3/s or similar. It's always good to look at the units: volume is m3, delivery rate is m3/s.
 

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