The discussion focuses on calculating the final velocity of mass m1 (7 kg) after an elastic collision with mass m2 (8 kg) at rest. The initial speeds are 3 m/s for m1 and 5 m/s for m2, which is at a 33-degree angle in the second quadrant. The correct final velocity of m1 is determined to be 3.59 m/s. Key equations used include momentum conservation and the elastic collision formulas, specifically vf=(2m/m1+m2)vx and vf=(m1-m2/m1+m2)vy.
PREREQUISITESStudents studying physics, particularly those focusing on mechanics and collision theory, as well as educators looking for practical examples of momentum conservation and elastic collisions.
ScienceGeek24 said:p=mv
ScienceGeek24 said:But this is an ellastic collision wouldn't it be vf=(2m/m1+m2)vx and vf=(m1-m2/m1+m2)vy ??
ScienceGeek24 said:hmmm still not 3.59m/s i divided the momentum of px/m=v and it gave me 1.79m/s ...
ScienceGeek24 said:Got it! Thanks man thankyou for your patience.
sciencegeek24 said:wait! On emore thing! I'm trying to find the kinetic energy lost i this one and this is what i did kef= 1/2(8kg+7kg)(3.52)^2=95.052 j and ke total= 1/2(8kg)(5m/s)^2+1/2(7kg)(3m/s)^2=131.5 j than i subtracted ktotal -kef= 44... Something something and that is not he right answer the right asnwer is 86.4j . What did i do wrong??