The problem involves an elastic collision between two masses, m1 and m2, where m1 has a mass of 7 kg and an initial speed of 3 m/s, and m2 has a mass of 8 kg and an initial speed of 5 m/s at an angle of 33 degrees in the second quadrant. After the collision, m2 remains at rest at the origin, and the task is to find the final velocity of m1, including both magnitude and direction.
The discussion is ongoing, with participants exploring various interpretations of the momentum vectors involved in the collision. Some have provided calculations for the momentum components, while others are seeking clarification on the proper approach to summing these components. There is no explicit consensus yet on the final velocity of m1.
Participants are grappling with the vector nature of momentum and the need to separate components along the x and y axes. There is also mention of potential confusion regarding the contributions of each mass to the overall momentum after the collision.
ScienceGeek24 said:p=mv
ScienceGeek24 said:But this is an ellastic collision wouldn't it be vf=(2m/m1+m2)vx and vf=(m1-m2/m1+m2)vy ??
ScienceGeek24 said:hmmm still not 3.59m/s i divided the momentum of px/m=v and it gave me 1.79m/s ...
ScienceGeek24 said:Got it! Thanks man thankyou for your patience.
sciencegeek24 said:wait! On emore thing! I'm trying to find the kinetic energy lost i this one and this is what i did kef= 1/2(8kg+7kg)(3.52)^2=95.052 j and ke total= 1/2(8kg)(5m/s)^2+1/2(7kg)(3m/s)^2=131.5 j than i subtracted ktotal -kef= 44... Something something and that is not he right answer the right asnwer is 86.4j . What did i do wrong??