Calculating Flux from a Permanent Magnet

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SUMMARY

This discussion focuses on calculating the flux from a permanent magnet, specifically Neodymium, for an alternator design. Key concepts include the 'Br' rating, which indicates the flux potential in a magnetic circuit, and the 'Hc' rating, which defines the opposing magnetic field intensity. The B-H curve is essential for understanding the relationship between these ratings, and the discussion explores the impact of air gaps and reluctance on the magnetic circuit. The user seeks confirmation on whether their method for determining the minimum thickness of the magnet will yield sufficient voltage at the desired RPM.

PREREQUISITES
  • Understanding of magnetic circuits and their analogies to electric circuits
  • Familiarity with B-H curves and their significance in magnetism
  • Knowledge of magnetic reluctance and its calculation
  • Basic principles of electromagnetism, including magnetomotive force (NI)
NEXT STEPS
  • Research the properties and applications of Neodymium magnets in alternators
  • Study the calculation of magnetic reluctance in circuits
  • Learn about the effects of air gaps on magnetic circuits and flux density
  • Explore advanced topics in electromagnetism, focusing on the B-H curve analysis
USEFUL FOR

Electrical engineers, mechanical engineers designing alternators, and anyone involved in the optimization of magnetic circuits and permanent magnet applications.

nickw1881
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I am hoping someone here has experience with permanent magnets. I have a theory on how to size a permanent magnet for an alternator I am designing, and I want someone to confirm that my technique will yield a result that is useful enough to go through the expense of building a prototype. My goal is to find the minimum thickness of Neodymium magnet that will produce the needed voltage at the RPM I plan to run.

First, permanent magnets as I understand them: Permanent magnets have a 'Br' rating, which is the amount of flux that would flow if this magnet were part of a magnetic circuit with 0 Reluctance. They also have an Hc rating, which defines the opposing magnetic field intensity that would result in 0 flux in that same magnetic circuit. If Br is plotted as a point on the vertical axis, and Hc as a point on the negative horizontal axis, then the curve between them is the B-H curve.

The B-H curve (most of it) is drawn by reducing the net flux in the circuit by A) Adding an air gap that will store potential energy as a magnetic field, or B) Using an electromagnet to create an H-field that opposes the one from the magnet. It is my understanding that a magnetic circuit is roughly analogous to an electric circuit, in that Kirchoff's loop law can be applied to both.

****If I add an air gap that has a reluctance of 10 Ampturn/Tesla, and there is 1 Tesla flowing through the circuit from the permanent magnet, then is that air gap the equivalent to using a coil to supply 10 amp turns opposing the permanent magnet flux? If the air gap and coil were swapped, would the total flux in the circuit remain the same: 1 Tesla?****

By choosing my air gap and core material, I can know the reluctance of my magnetic circuit. I will take that reluctance, multiply it with the chosen flux density (flux needed to produce rated voltage@rpm) to get H opposing. Br is constant, no matter how thick or thin the magnet is, and since Hc is rated per unit length, I should be able to scale the H axis of the B-H curve to find the correct magnet thickness. It should be similar to how I would do per-unit calculations or normalized filter design in other EE calculations.
 
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In magnetic circuits, the conserved quantity corresponding to electric current is magnetic flux. Where B is measured in Tesla, or Webers per square meter, then the flux, Phi is in units of Webers. \Phi = \int B \cdot dA_e The flux passing through any cross section of the magnetic circuit is the same when leakage flux is taken into consideration.

Another useful quantity, akin to Kirchhoff's voltage law is the integral of H around the loop. Magnetomotive force, NI = NI = \oint H \cdot dl_e. dl_e is an element of the magnetic path. NI is current times number of turns of wire. It is the equivalent of a voltage source. Unfortunately, I'm unclear how permanent magnets or magnetic reluctance might modify this equation.
 
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