Calculating Force and Speed of a Snooker Ball

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Homework Help Overview

The discussion revolves around calculating the speed of a snooker ball after being struck by a cue, given the force applied, the mass of the ball, and the duration of the impact. The subject area includes concepts of impulse and momentum in physics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between force, mass, and velocity through the impulse-momentum theorem. There are attempts to manipulate the equations to find the final speed of the ball, with some participants expressing uncertainty about the next steps in their calculations.

Discussion Status

Some participants have provided guidance on using the impulse-momentum relationship to find the final velocity. However, there appears to be a lack of clarity on the specific steps to take next, as some participants reiterate previous calculations without reaching a resolution.

Contextual Notes

There is a mention of the initial velocity being zero and the need to plug in known values to solve for the final speed. The discussion reflects a collaborative effort to clarify the problem without reaching a definitive conclusion.

glasgowm
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A cue exerts an average force of 7N on a stationary snooker ball of mass 200g if the impact lasts for 45ms, with what speed does the ball leave the que?

---

Ft = mv - mu
F = m(v-u/t)
F = 0.2(v-0/0.0045)
= 0.2v/0.0045 = 44.4444V

Can't figure out what the next step is from my notes.

Cheers
 
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glasgowm said:
A cue exerts an average force of 7N on a stationary snooker ball of mass 200g if the impact lasts for 45ms, with what speed does the ball leave the que?

---

Ft = mv - mu
F = m(v-u/t)
F = 0.2(v-0/0.0045)
= 0.2v/0.0045 = 44.4444V

Can't figure out what the next step is from my notes.

Cheers

Simply stated, the impulse equals the change of linear momentum, so, you have: [tex]F\cdot t = mv_{2}-mv_{1}[/tex], where m is the mass of the ball, v2 the final velocity and v1 the initial velocity (equals zero). From this equation you can easily retrieve v2.
 
radou said:
Simply stated, the impulse equals the change of linear momentum, so, you have: [tex]F\cdot t = mv_{2}-mv_{1}[/tex], where m is the mass of the ball, v2 the final velocity and v1 the initial velocity (equals zero). From this equation you can easily retrieve v2.
I already did that.
 
glasgowm said:
I already did that.

I saw you did that and I don't see where the problem is. Just plug in the force and solve to get the speed v.
 

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