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Calculating force between links in a chain

  1. Oct 7, 2012 #1
    A chain consisting of five links, each of mass 0.145 kg, is lifted vertically with a constant acceleration of a = 2.6 m/s2.
    Consider the force link 3 exerts on link 2. (Chains are numbered 5 to 1 going down)


    Find the magnitude of this force.


    F=ma


    I don't know what to consider to find the answer. I tried doing a free body diagram, but I don't know what forces to add on it.
    I tried F=ma --> a=2.6 m/s^2 and m=.145 kg
    That didn't work, so I tried adding the downward force F=ma --> a=9.8 m/s^2 and m= .145 kg and that didn't work either.
    How do I proceed?
     
    Last edited: Oct 7, 2012
  2. jcsd
  3. Oct 7, 2012 #2
    Never mind, I found the answer
     
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