A chain consisting of five links, each of mass 0.145 kg, is lifted vertically with a constant acceleration of a = 2.6 m/s2. Consider the force link 3 exerts on link 2. (Chains are numbered 5 to 1 going down) Find the magnitude of this force. F=ma I don't know what to consider to find the answer. I tried doing a free body diagram, but I don't know what forces to add on it. I tried F=ma --> a=2.6 m/s^2 and m=.145 kg That didn't work, so I tried adding the downward force F=ma --> a=9.8 m/s^2 and m= .145 kg and that didn't work either. How do I proceed?