Calculating Force for an Exceptional Standing Jump: Physics Homework Problem

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SUMMARY

The discussion centers on calculating the force required for a 66 kg person to achieve a standing jump height of 0.80 meters. The initial calculations provided by a participant indicate that the gravitational force acting on the person is 9.81 m/s², leading to a calculated work of 517.968 Joules. However, the crouching distance of 0.20 meters prior to the jump must also be considered to accurately determine the total force exerted against the ground. The final force calculation should incorporate both the jump height and the crouching distance for precision.

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PearlyD
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Homework Statement


An exceptional standing jump would raise a person 0.80m off the ground. To do this, what force must a 66 kg person exert against the ground?
Assume the person crouches a distance of 0.20 m prior to jumping,and thus the upward force has this distance to act over before he leaves the ground.



This question i don't even know how to start
can some one explain how to even start it?
 
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Work = Force * Distance
Force = (9.81)(66)
Work = (9.81)(66)(.80)
Work = 517.968 J

Doesn't account for the crouching distance, but it may be irrelevant, someone else will probably cover that. I hope I went in the right direction with this.
 

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