Calculating Force Needed to Lift a Rock with a Crowbar

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The discussion focuses on calculating the force required to lift a 500 Newton rock using a 2.0 meter long crowbar, with the fulcrum positioned 0.5 meters from the rock. The correct equation to use is the lever principle, represented as f1d1 = f2d2, where f1 is the applied force, d1 is the distance from the fulcrum to the applied force, f2 is the weight of the rock, and d2 is the distance from the fulcrum to the rock. By substituting the values, the correct force needed is determined to be 200 Newtons, confirming the initial calculation.

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What equation is used to solve a problem similar to the one below?

What force must be applied to the end of a 2.0 meter long crowbar in order to lift
a 500 Newton rock if the fulcrum of the bar is .5 meters from the rock?

Thanks.
 
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Would it be something like f1d1=f2d2?
Therefore, (500 N)(2.0 meters) = (x N)(0.5 meters). And the answer is 200 N?
 
fiosuer said:
Would it be something like f1d1=f2d2?
Therefore, (500 N)(2.0 meters) = (x N)(0.5 meters). And the answer is 200 N?

THe equation is correct.. What is means is that f1 is applied at distance d1 from the fulcrum and F2 is applied a distance d2 from the fulcrum.

I recommend that you sketch the situation to help select the correct values to substitute.
 
Fewmet said:
THe equation is correct.. What is means is that f1 is applied at distance d1 from the fulcrum and F2 is applied a distance d2 from the fulcrum.

I recommend that you sketch the situation to help select the correct values to substitute.

Is it 2.0 - 0.5 = 1.5?
(500 N)(1.5 meters) = (x N)(0.5 meters). And the answer is 1500N?
 
fiosuer said:
Is it 2.0 - 0.5 = 1.5?
(500 N)(1.5 meters) = (x N)(0.5 meters). And the answer is 1500N?

That would be true of the 500 N rock were 1.5 m from the fulcrum. THe questions says it is 0.5 m from the fulcrum.
 

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