Calculating Force Needed to Lift a Rock with a Crowbar

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Homework Help Overview

The discussion revolves around calculating the force required to lift a rock using a crowbar, specifically focusing on the lever principle and the distances involved in the setup.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the application of the lever equation, questioning the correct distances and forces involved in the calculation. There is a focus on the relationship between the forces and their respective distances from the fulcrum.

Discussion Status

Some participants have provided guidance on the use of the lever equation and suggested sketching the situation to clarify the values. However, there are differing interpretations of the distances involved, leading to multiple calculations and results being proposed.

Contextual Notes

Participants are discussing the specific distances from the fulcrum as stated in the problem, with some confusion regarding the placement of the rock and the application of the lever principle.

fiosuer
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What equation is used to solve a problem similar to the one below?

What force must be applied to the end of a 2.0 meter long crowbar in order to lift
a 500 Newton rock if the fulcrum of the bar is .5 meters from the rock?

Thanks.
 
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Would it be something like f1d1=f2d2?
Therefore, (500 N)(2.0 meters) = (x N)(0.5 meters). And the answer is 200 N?
 
fiosuer said:
Would it be something like f1d1=f2d2?
Therefore, (500 N)(2.0 meters) = (x N)(0.5 meters). And the answer is 200 N?

THe equation is correct.. What is means is that f1 is applied at distance d1 from the fulcrum and F2 is applied a distance d2 from the fulcrum.

I recommend that you sketch the situation to help select the correct values to substitute.
 
Fewmet said:
THe equation is correct.. What is means is that f1 is applied at distance d1 from the fulcrum and F2 is applied a distance d2 from the fulcrum.

I recommend that you sketch the situation to help select the correct values to substitute.

Is it 2.0 - 0.5 = 1.5?
(500 N)(1.5 meters) = (x N)(0.5 meters). And the answer is 1500N?
 
fiosuer said:
Is it 2.0 - 0.5 = 1.5?
(500 N)(1.5 meters) = (x N)(0.5 meters). And the answer is 1500N?

That would be true of the 500 N rock were 1.5 m from the fulcrum. THe questions says it is 0.5 m from the fulcrum.
 

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