Calculating force nessary to compress spring

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SUMMARY

The discussion centers on calculating the force required to compress a spring using Hooke's Law and Newton's Second Law. Given a mass of 0.12 kg, a spring constant of 30 N/m, and a compression distance of 3.6 cm, the force can be calculated as 10.8 N. Additionally, the resulting deceleration of the mass due to this force is determined to be 90 m/s². The conversation highlights the application of fundamental physics principles in solving real-world problems.

PREREQUISITES
  • Understanding of Hooke's Law
  • Familiarity with Newton's Second Law of Motion
  • Basic knowledge of force, mass, and acceleration calculations
  • Ability to convert units (e.g., cm to m)
NEXT STEPS
  • Study Hooke's Law applications in various mechanical systems
  • Explore advanced topics in dynamics, focusing on force and acceleration
  • Learn about energy stored in springs and potential energy calculations
  • Investigate real-world applications of spring mechanics in engineering
USEFUL FOR

Students studying physics, educators teaching mechanics, and engineers working with spring systems will benefit from this discussion.

nikelberry
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The data for a ball and spring sensor is given below:
mass of ball = 0.12kg
spring constant = 30Nm-1
distance to be compressed = 3.6cm

Calculate the force nessary to compress spring by 3.6cm.
The deceleration which the force in (the 1st question) would cause in a mass of 0.12kg.

i seem to find this question quite tricky, mainly becasue I am not sure of what equation to use!
please me on this one!
 
Physics news on Phys.org
What does Hooke's law tell you about springs and Newton's 2nd law tell you about acceleration?
 
yay! i got it! thanks for your help much appreciated!
and that's my homework done!
 

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