Calculating Force of a Falling Book: Mass, Velocity, and Impact Time"

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The discussion focuses on calculating the force exerted by a falling book upon impact with the floor using Newton's second law in impulse form. Given a mass of 1.5 kg, an impact velocity of 3 m/s, a rebound velocity of 1 m/s, and an impact duration of 0.3 seconds, the change in velocity (Δv) is determined to be 2 m/s. Applying the impulse equation F · Δt = m · Δv, the force can be calculated as 10 N, indicating the force exerted by the book on the floor during the impact.

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a book falls off a bookshelf and hits the floor. given this info calculate the force of the book on the floor.
mass of the book 1.5kg the book touched the floor for .3 sec. the velocity of the book the moment the book hit the floor 3m/s.
the velocity of the book when it bounced off the floor 1m/s.
 
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Apply Newton's second law in the impulse form.

[tex]F \cdot \Delta t = m \Delta v[/tex]
 
Further explanation: This formula can be called the impulse equation. It says that a Force acting over some period of Time [tex]\Delta t[/tex] will create a change in momentum or velocity [tex]\Delta v[/tex].

Analyze the situation:
What is the change in the velocity of the book before and after impact?
How much time did it take for this change in velocity to happen?
Mass is given.

Can we then solve for force?
 

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