Calculating Force of a Nail Stopping a Hammer with Constant Acceleration

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SUMMARY

The discussion focuses on calculating the force exerted by a nail when a hammer is stopped under constant acceleration. The scenario involves a hammer weighing 9.8N, with a downward force of 50N applied by a man, and a stopping distance of 0.50cm. The key equations referenced include the work-energy principle, specifically the relationship between work done (wtotal) and kinetic energy (K), where wtotal = K2 - K1. The participant is encouraged to analyze the forces acting on the hammer and the nail to determine the nail's force.

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  • Understanding of Newton's laws of motion
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  • Knowledge of the work-energy principle
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Homework Statement



A man applies 50N downward force on a 9.8N
hammer. V0=5.0m/s. Stopped by a nail in d=0.50cm
• Assuming constant acceleration: Fnail/hammer
=?

Homework Equations





The Attempt at a Solution



I am completely stumped on how to start this problem. What I have done so far is.

Make two free body diagrams one for the force being applied by the man and one for the hammer.

I know the nail is 0.005m

I know I have to do some form of wtotal= K2-K1

I tried solving for K using 1/2mv^2 and since the acceleration is constant K1 will be 0 , and I rearranged the formula wtotal= k2-k1 to be wtotal +0=k2

I have no idea what else I can do. Guidance will be greatly appreciated.

Higgenz
 
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If the acceleration is constant what does this tell you about the force creating the acceleration? Is it changing in time? What is the relation between force, distance parallel to the force, and work?
 

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