Calculating force of Arbor Press

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SUMMARY

The discussion focuses on calculating the output force of an arbor press with a lever arm of 12 inches and a gear pitch diameter of 1.5 inches. To achieve a force of 300 lbs at the arbor head, the torque applied to the shaft (Ta) is determined by the equation Ta = F-pull X 12 inches. The force output by the gear teeth onto the arbor ram (Fa) is calculated using the formula Fa = Ta/1.5 inches, factoring in mechanical efficiencies. A free body diagram is recommended for a clearer understanding of the mechanics involved.

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Spoolx
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Hey all,
So I was trying to calculate the output force of an arbor press given a specific input force.

There is no gear reduction, the lever arm is 12" and the gear pitch diameter is 1.5"

Basically I want to know how much force do I need to apply to the lever arm to produce 300lbs at the arbor head.

I broke out my statics book and I don't see anything exactly like this so I am not sure if its a simple moment calculation.

Any guidance is appreciated

Thanks!
 
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There is no gear reduction
Not exactly.

Torque applied to shaft Ta = F-pull X 12 inches (assume best case 90-degrees force vector)
Force output by gear teeth onto arbor ram = Fa = Ta/1.5 inch

Less efficiencies.
 
Thanks for the reply, can you tell me what equation your solution refers to?

Thanks
 
The variable names are abitrary. The solution is basic mechanics. You should do a free body diagram to get this.
 

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