Understanding Torque Transfer in Coupled Objects

  • Thread starter Thread starter smiller15
  • Start date Start date
  • Tags Tags
    Coupled Torque
Click For Summary
SUMMARY

This discussion focuses on the calculation of torque transfer from a DC motor to a worm gear. The key equation presented is Fwt = (2*M1)/d1, where Fwt represents the tangential force, M1 is the motor torque, and d1 is the diameter of the worm. It is established that the torque output from the motor, denoted as X Nm, directly translates to the torque on the worm gear, regardless of the differing shaft diameters. Therefore, no modification of the torque value is necessary before using it in the tangential force equation.

PREREQUISITES
  • Understanding of torque and its relationship to force and diameter
  • Familiarity with DC motors and their torque output
  • Basic knowledge of worm gear mechanics
  • Ability to apply mathematical equations in mechanical contexts
NEXT STEPS
  • Research the principles of torque transfer in mechanical systems
  • Learn about the mechanics of worm gears and their applications
  • Study the impact of shaft diameter on torque transmission
  • Explore advanced calculations for tangential and axial forces in coupled systems
USEFUL FOR

Mechanical engineers, robotics enthusiasts, and anyone involved in the design and analysis of motor-driven systems, particularly those utilizing worm gears.

smiller15
Messages
1
Reaction score
0
Hello All,
I have a quick question about torque and how it transfers to a coupled object. I am coupling a DC motor onto a worm gear and I need to calculate the tangential and axial forces on the worm. The Tangential Force equation is as follows:

Fwt = (2*M1)/d1 where Fwt is the tangential force of the worm, M1 is defined as the worm torque and d1 is the referenced diameter of the worm.

My question stems from the M1 variable and is it just simply the output torque from the motor it is coupled to or would I need to modify the torque value before I input it into the tangential force equation? The only reason I am questioning things is due to torque being dependent upon the length of the lever arm (shaft diameter in this case) and the worm gear shaft is larger than my motor shaft.

I appreciate any help into my confusion.
 
Engineering news on Phys.org
smiller15 said:
The only reason I am questioning things is due to torque being dependent upon the length of the lever arm (shaft diameter in this case) and the worm gear shaft is larger than my motor shaft.

I'm not familiar with the equation you mention (not my field) but the above is wrong.

If the system loads up the motor so that the motor is generating X Nm of torque then that's the torque in the motor shaft regardless of the shaft diameter of the motor. If the worm is connected to the motor shaft then the worm torque is also X Nm.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
8K
  • · Replies 2 ·
Replies
2
Views
4K
Replies
2
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
5
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K