UMath1
- 361
- 9
Ok. I know that there is no difference between the friction force and the force the tire imparts to the ground and they equal and opposite. What I was saying is that Eout is not entirely Eout, because the wheel is part of the bike. I know that Iadθ is the energy that goes into rotating the wheel giving it rotational kinetic energy, but the wheel also gains translational kinetic energy from a portion of mαr^2dθ. I thought this portion was Mw/Mbike.