Calculate output forces of machines

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SUMMARY

The discussion focuses on calculating the output forces of machines, specifically in the context of bicycles and levers. It establishes that the output force is not simply a function of input torque but is influenced by factors such as angular acceleration and mass distribution. The equation for the output force of a bicycle wheel is derived as (Ft*Rg)/(Rw) * (M + mf)/(M + mf + mw), where Ft is the force applied to the rear gear, Rg is the radius of the rear gear, Rw is the radius of the rear wheel, and M, mf, and mw represent the masses of the bike+rider system, front wheel assembly, and rear wheel assembly, respectively. The conversation emphasizes the importance of accounting for both linear and angular accelerations in force calculations.

PREREQUISITES
  • Understanding of Newton's second law (F=ma)
  • Familiarity with torque and rotational dynamics
  • Knowledge of basic mechanical principles related to levers and gears
  • Ability to perform calculations involving mass and acceleration
NEXT STEPS
  • Study the principles of torque and angular acceleration in mechanical systems
  • Learn about the dynamics of bicycle mechanics and force transmission
  • Explore the concept of work-energy principles in mechanical systems
  • Investigate the effects of friction and mass distribution on output forces
USEFUL FOR

Mechanical engineers, physics students, bicycle mechanics, and anyone interested in understanding the dynamics of force output in machines.

  • #31
Ok. I know that there is no difference between the friction force and the force the tire imparts to the ground and they equal and opposite. What I was saying is that Eout is not entirely Eout, because the wheel is part of the bike. I know that Iadθ is the energy that goes into rotating the wheel giving it rotational kinetic energy, but the wheel also gains translational kinetic energy from a portion of mαr^2dθ. I thought this portion was Mw/Mbike.
 
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  • #32
Does that make any sense?
 

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