Calculating force of Arbor Press

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Discussion Overview

The discussion revolves around calculating the output force of an arbor press based on a specified input force, focusing on the mechanics involved without gear reduction. Participants explore the relationship between input force, lever arm length, and output force at the arbor head.

Discussion Character

  • Technical explanation, Conceptual clarification, Mathematical reasoning

Main Points Raised

  • One participant seeks to determine the input force required to achieve 300 lbs at the arbor head, given a lever arm of 12 inches and a gear pitch diameter of 1.5 inches.
  • Another participant suggests that torque applied to the shaft can be calculated as the product of the pulling force and the lever arm length, assuming an optimal force vector angle.
  • A further claim indicates that the output force exerted by the gear teeth onto the arbor ram can be derived from the torque divided by the gear pitch diameter.
  • One participant recommends using a free body diagram to clarify the mechanics involved in the calculation.

Areas of Agreement / Disagreement

Participants have not reached a consensus on the specific equations or methods to use for the calculations, and there are differing views on the best approach to solve the problem.

Contextual Notes

There is mention of efficiencies not being accounted for in the calculations, which may affect the output force. Additionally, the variable names used in the proposed solutions are described as arbitrary.

Spoolx
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Hey all,
So I was trying to calculate the output force of an arbor press given a specific input force.

There is no gear reduction, the lever arm is 12" and the gear pitch diameter is 1.5"

Basically I want to know how much force do I need to apply to the lever arm to produce 300lbs at the arbor head.

I broke out my statics book and I don't see anything exactly like this so I am not sure if its a simple moment calculation.

Any guidance is appreciated

Thanks!
 
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There is no gear reduction
Not exactly.

Torque applied to shaft Ta = F-pull X 12 inches (assume best case 90-degrees force vector)
Force output by gear teeth onto arbor ram = Fa = Ta/1.5 inch

Less efficiencies.
 
Thanks for the reply, can you tell me what equation your solution refers to?

Thanks
 
The variable names are abitrary. The solution is basic mechanics. You should do a free body diagram to get this.
 

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