Calculating Force on a Ball at an Angle

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SUMMARY

The discussion focuses on calculating the force exerted by a wall on a ball with a mass of 100g, striking at a speed of 5 m/s at a 60-degree angle. The correct force is determined to be 250√3 N, directed to the left, after accounting for the change in velocity during the collision. The solution involves analyzing the acceleration in the x-direction, as the ball rebounds with the same speed but in the opposite direction. The contact time during the collision is specified as 2 x 10^-3 seconds.

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Homework Statement



a mass of 100g strikes the wall with speed 5 m/s at an angle of 60 degrees to the wall and it rebounds with the same speed. if the contact time is 2 * 10^ -3 , what is the force applied by the wall and in what direction?

The Attempt at a Solution

I tried solving the question by using the wall as the y-axis and finding the acceleration along the y component of the velocity..
but I come up with the answer 250 which is wrong
the correct answer is 250 * underoot 3 and the direction is given to the left please explain how

thanks in advance
 
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Hello scary one,

You may assume there is no force (so no acceleration) in the y direction: the ball appears to bounce off with the same speed.

In the x-direction, however, drastic things happen: first it moves at some speed towards the wall and after the bounce it has the same speed but in a negative x direction. So there is a big ##\Delta v##. Your job is to calculate a from that with the relevant formula (oops :wink: )
 
thanks bvu.
I got it right now.
 

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