- #1

predentalgirl1

- 67

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**1. A horizontal magnetic field of 1.0 x 10^-4 T is at an angle of 30 degrees to the direction of the current in a straight, horizontal wire 75 cm long. If the wire carries a current of 15 A, what is the magnitude of the force on the wire?**

**2.B be the magnetic field = 1.0 x 10-4 T**

Θ be the angle between the magnetic field and current = 300

L be the length of the wire = 75 cm = 0.75m

I be the current in the wire = 15 A

F be the force in the wire ?

From basic magnetic force

F = qvB sin Θ

F = q(L/t)B sin Θ

F = (q/t)LB sin Θ

F = I L B sin Θ

Θ be the angle between the magnetic field and current = 300

L be the length of the wire = 75 cm = 0.75m

I be the current in the wire = 15 A

F be the force in the wire ?

From basic magnetic force

F = qvB sin Θ

F = q(L/t)B sin Θ

F = (q/t)LB sin Θ

F = I L B sin Θ

**3. F = 15 x 0.75 x 1.0x10-4 sin 300**

F = 11.25 x 10-4 sin 300

F = 11.25 x 10-4 (1/2)

F = 5.625 10-4 N

F = 0.5625mN

(Ans)

F = 11.25 x 10-4 sin 300

F = 11.25 x 10-4 (1/2)

F = 5.625 10-4 N

F = 0.5625mN

(Ans)