- #1

Ishida52134

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## Homework Statement

A uniform ladder is 10m long and weighs 400 N. It rests with its upper end against a frictionless

vertical wall. Its lower end rests on the ground and is prevented from slipping by a peg driven

into the ground. The ladder makes a 30◦ angle with the horizontal. The magnitude of the

force exerted on the peg by the ladder is:

A. zero

B. 200N

C. 400N

D. 470N

E. 670N

## Homework Equations

torque = r x F

## The Attempt at a Solution

First I identified the forces. So normal force, frictional force, weight, and force from the wall and force from the peg which acts horizantally.

Basically, I just took moments about the base of the ladder. I got -400(5cos30) + 5Fw = 0.

Then I solved for Fw getting 346.

Then I set all x forces equal to each other. Getting 346 = Fpeg + Ffrictional.

And I got stuck lol.

I don't know if there's no frictional force at all and that the peg is acting in place of it or if it's the sum of them together that provides the x component.