1. The problem statement, all variables and given/known data Figure attached A uniform ladder is 10 m long and weighs 400 N. It rests with its upper end against a frictionless vertical wall. Its lower end rests on the ground and is prevented from slipping by a peg driven into the ground. The ladder makes a 30 degree angle with the horizontal. The magnitude of the force exerted on the peg by the ladder is: W = 400N L = 10m Answer: 470N 2. Relevant equations Torque = r x F 3. The attempt at a solution Calculating torque about the lower end, I was able to find force exerted by the wall Tweight = Twall 400N(5cos30) = Fwall(10sin30) Fwall = 346.4N the forces I have so far are: normal force, weight and force from the wall. Are there two other forces from the peg(perpendicular to the ladder going down) and the force of the ladder on the peg(perpendicular to ladder up)?