Calculating Force Problems on Toy Car

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SUMMARY

The discussion focuses on calculating the forces acting on a toy car with a mass of 7.79 kg, moving in a circular track with a radius of 38.5 m. The car accelerates from rest to a final speed of 5.13 m/s over 6 seconds. The inward force required to maintain circular motion is calculated using the formula F=mv²/r, resulting in a magnitude of 5.32 N. The tangential force, which is equivalent to a linear force problem, was also addressed, leading to a successful resolution by the participants.

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  • Understanding of Newton's Second Law (F=ma)
  • Knowledge of circular motion dynamics
  • Familiarity with kinematic equations
  • Basic algebra for force calculations
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  • Learn about kinematic equations for uniformly accelerated motion
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[SOLVED] force problems

A 7.79 kg toy car now starts at rest and is going around a circular track of radius 38.5 m, the accelerates at a constant rate to a final speed of 5.13 m/s in 6 seconds. At the instant it reaches its final speed, find:1.the magnitude of the inward force needed to keep it moving in a circle
2.the magnitude of the tangential force

F=ma
a=v2/r

question1. F=mv2/r=7.79(5.13)(5.13)/38.5=5.32. and that's is right.
question2. the magnitude of the tangential force, i don't know what to do with it ,can anybody help me?
 
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The tangential force problem is the same as a linear force problem. 0->5.13m/sec in 6sec. How much force?
 
thank you for help. i got the answer.
 

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