Calculating Force to Change Earth's Orbit - Kepler

Click For Summary
SUMMARY

To change Earth's orbit, the force applied must be calculated based on the desired outcome, taking into account the elliptical nature of the orbit. The centripetal force equation, M_Earth.v^2/distance, is not sufficient as it assumes a circular orbit. Instead, the direction of the force is crucial: to raise the orbit, apply force in the same direction as Earth's motion; to lower it, apply force in the opposite direction. The calculated force of 3.54 x 10^22 Newtons is relevant but must be contextualized within the specific orbital change desired.

PREREQUISITES
  • Understanding of Newton's Law of Universal Gravitation
  • Familiarity with centripetal force calculations
  • Knowledge of orbital mechanics and elliptical orbits
  • Basic physics concepts related to force and motion
NEXT STEPS
  • Research the implications of elliptical orbits in celestial mechanics
  • Study the effects of force direction on orbital changes
  • Explore advanced calculations for orbital transfers, such as Hohmann transfers
  • Learn about gravitational assists and their applications in space missions
USEFUL FOR

Astronomers, astrophysicists, aerospace engineers, and students of physics interested in orbital mechanics and celestial navigation.

kepler
Messages
28
Reaction score
0
Hi,

If we were to change the Earth's orbit, what force should we apply and in what direction? Shoud we go against G.(M_Earth + M_Sun) / distance^2 or against the centripetal force, M_Earth.v^2/distance?

I've calculated this last one and I got the result:

3,542396634E+22 Newtons

Is this correct?

Regards,

Kepler
 
Physics news on Phys.org
The problem with mv^2/r is that you've assumed the Earth is in a circular orbit. It is, in fact, somewhat elliptical. That difference drastically changes the problem.
 
It really depends on how you want to change the orbit.(what kind of an orbit do you want after the change?) If you want to raise it to an higher orbit, you have to push it in the same direction it is moving around the Sun. If you want to move it into a lower orbit, you push in the opposite direction. If you push directly towards or away from the Sun, you will change the shape of the orbit such that it will be closer to the Sun at part of its orbit and further at another part. If you push it at a right angle to its orbital plane, you will change the inclination or "tilt" of the orbit.
 
In sci-fi when an author is talking about space travellers or describing the movement of galaxies they will say something like “movement in space only means anything in relation to another object”. Examples of this would be, a space ship moving away from earth at 100 km/s, or 2 galaxies moving towards each other at one light year per century. I think it would make it easier to describe movement in space if we had three axis that we all agree on and we used 0 km/s relative to the speed of...

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 20 ·
Replies
20
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 22 ·
Replies
22
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K