Calculating Force Using Young's Modulus

Click For Summary
SUMMARY

The discussion focuses on calculating force using Young's Modulus, specifically addressing the challenge of determining both force (F) and cross-sectional area (Ao) when only certain parameters are known. The formula derived is F = (E * Ao * ΔL) / Lo, where E is the Young's Modulus constant (2.106), ΔL is the change in length (10mm), and Lo is the original length (200mm). Participants highlight that without knowing either F or Ao, it is impossible to solve for the other variable, emphasizing the interdependence of these parameters in the calculations.

PREREQUISITES
  • Understanding of Young's Modulus and its application in material science
  • Basic knowledge of stress and strain concepts
  • Familiarity with algebraic manipulation of equations
  • Ability to interpret physical properties of materials
NEXT STEPS
  • Research how to calculate strain from change in length and original length
  • Learn about the relationship between stress and force in materials
  • Explore methods for determining cross-sectional area in different geometries
  • Study practical applications of Young's Modulus in engineering and materials testing
USEFUL FOR

Students and professionals in engineering, materials science, and physics who are involved in mechanical analysis and material property evaluation will benefit from this discussion.

MissAlex
Messages
2
Reaction score
0
1. How to calculate cross sectional area and force for Young's Modulus? My main issue is that I don't know my F or my Ao. Help?
e=Constant 2.106
DeltaL=10mm
Lo (original length of elastic)= 200mm
f=?
Ao=?


2. E= FLo
Ao(Delta)L
F= EAoDeltaLength[U/]
Lo
F= (2.106)(10mm)(Ao)
200mm


3. There are two unknown variables! How can I do this?
 
Physics news on Phys.org
Interesting. From the given change in length and original length, you can calculate the strain. Then you can multiply with E to obtain the stress. But you can't calculate the area if the force is unknown, and vice versa.
 
Right.
What is the force though? How can force be calculated?
How is cross-sectional area calculated?
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 29 ·
Replies
29
Views
8K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
2K
Replies
1
Views
6K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
3K
  • · Replies 7 ·
Replies
7
Views
16K
Replies
2
Views
2K