# Relationship of Young's modulus and impulse force

## Homework Statement

Is that possible to obtain the a relationship between Young's modulus of a spring and impulse force with below information ? I personally think that we cannot if without the given cross-sectional area A and the given spring constant k.

The particle is connect to a elastic spring, then an external impulse force horizontally was added to it.
(Smooth plate)

The given values are :

Particle mass ''m'', spring of modulus of elasticity ''E'', spring's natural length ''L'', received impulse ''J'', impulse reaction time ''t'', displacement ''x''

2. Homework Equations ## The Attempt at a Solution

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F = kx => J/t = (EA/L) * (x)

Looks like the area is an essential value or we cannot express the equation for them.

haruspex
Homework Helper
Gold Member E there is not Young's modulus of a spring. Young's modulus, often written as Y, is related to the spring constant k by Y=kL0.
F = kx => J/t
Not in this case. J=∫F.dt. You can only simplify that to J=Ft if F is constant.

E there is not Young's modulus of a spring. Young's modulus, often written as Y, is related to the spring constant k by Y=kL0.

Not in this case. J=∫F.dt. You can only simplify that to J=Ft if F is constant.
Thanks for this reminding.

For Y=k*L0, may I know why you can remove the A (cross sectional area) ?

haruspex
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