Calculating Forces on Two Charges Above a Conducting Sheet

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SUMMARY

The discussion focuses on calculating the forces acting on two charges, +Q and -Q, positioned a horizontal distance 'a' apart and a vertical distance 'b' above a large conducting sheet. The user attempted to solve the problem using the method of image charges, resulting in a complex expression for the force, F. The derived expression for the force components is F = kQ^2 times vector ( [1/a^2 - a/(a^2 + 4b^2)^3/2], 0, [2b/(a^2 + 4b^2)^3/2 - 1/4b^2] ). The user confirms that these represent vector components of the forces acting on the charges.

PREREQUISITES
  • Understanding of electrostatics and Coulomb's law
  • Familiarity with the method of image charges
  • Knowledge of vector calculus
  • Basic principles of conductors in electrostatic equilibrium
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  • Study the method of image charges in electrostatics
  • Learn how to derive force components in vector form
  • Explore the implications of conducting sheets on electric fields
  • Investigate the mathematical techniques for simplifying complex expressions
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Students and professionals in physics, particularly those studying electrostatics, as well as educators looking for examples of force calculations involving charges and conducting surfaces.

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Homework Statement



Two charges +Q and -Q are a horizontal distance a apart and a vertical distance b above a large conducting sheet. Find the components of the forces acting on each charge.

Homework Equations





The Attempt at a Solution



Ok well I've tried to solve this using image charges (i.e. positing 2 imaginary charges below the plate) and have got an expression for F. My problem is that the expression is really horrible so i can't find the modulus of the vector bit and thus write it in components.. have i gone wrong?

my answer is F = kQ^2 times vector ( [1/a^2 - a/(a^2 + 4b^2)^3/2] , 0 , [2b/(a^2 + 4b^2)^3/2 - 1/4b^2] )

Thanks!
 
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Those look like vector components from where I'm sitting! :smile:
 

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