Electric field between conducting and non-conducting sheets

  • #1

Homework Statement



Two infinite sheets of charges are placed parallel to each other. If the sheet on the left is non conducting and have a uniform charge density 3(sigma) and the one on the right is conducting and has a uniform charge density (sigma). If the area on both plates is 1m^2 then calculate the value of electric field at (a) to the left of left sheet (b) in between the sheets (c) to the right of right sheet.

Homework Equations


gauss law E= (sigma)/2€o
E=(sigma)/€o


The Attempt at a Solution


I am attempting it to do it by definitions. I think that the field at the right of the right sheet will be 0 because right sheet is conducting but I don't know if at the left of left sheet the value will be sum of two fields of the sheets or not and what will be the electric field at middle
 

Answers and Replies

  • #2
Doc Al
Mentor
45,029
1,326
the one on the right is conducting and has a uniform charge density (sigma)
This is unclear: Does this include the charge density on both sides of the plate? (I would assume so: The total charge density is sigma.)

I think that the field at the right of the right sheet will be 0 because right sheet is conducting
The field within the material of the conducting plate must be zero, but not outside it.
 
  • #3
This is unclear: Does this include the charge density on both sides of the plate? (I would assume so: The total charge density is sigma.)
yes I guess so. But its not mention in the question.
 
  • #4
Doc Al
Mentor
45,029
1,326
So you're saying that the charged sheet has a surface charge of 3σ and the conducting sheet has a charge of σ?
 
  • #6
Doc Al
Mentor
45,029
1,326
Yeah, quite a bit about this problem statement is not quite clear. Can you post it exactly as it appears, word for word?
 
  • #7
you're
yes. they have given us symbols inspite of numeric values. We have to drive formulas for it. and thats the exact wordings that are written in my note book.
 
  • #8
Doc Al
Mentor
45,029
1,326
Well, ignoring the fact that the "infinite" sheets have an area of 1 m^2, you can just treat them as infinite sheets of charge. Unless there is more to this question, the fact that one is a conducting sheet is irrelevant.
 
  • #9
Delta2
Homework Helper
Insights Author
Gold Member
3,562
1,375
I think if the conducting sheet has some small width ##\Delta x## then we ll have to calculate the induced charged density on it and we can speak of the inner and outer surface charge densities on it.. However If its width is zero , so it is purely 2Dimensional then we don't have to bother with that.
 
  • #10
Doc Al
Mentor
45,029
1,326
Assuming you're given the total surface charge on the conducting plate (both sides total), you won't have to worry about any induced surface charges since they don't ask for that.
 

Related Threads on Electric field between conducting and non-conducting sheets

Replies
11
Views
7K
Replies
9
Views
152
Replies
1
Views
176
Replies
3
Views
18K
Replies
5
Views
4K
Replies
2
Views
2K
  • Last Post
Replies
1
Views
1K
Replies
17
Views
11K
Replies
1
Views
6K
Top