Calculating Free Energy: Standard Enthalpy and Entropy at 32C

  • Thread starter Thread starter Soaring Crane
  • Start date Start date
  • Tags Tags
    Energy Free energy
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
5 replies · 10K views
Soaring Crane
Messages
461
Reaction score
0
Calculate the gibbs free energy for a reaction which has a standard enthalpy = -196kJ/mol and standard entropy = 151 J/K mol at 32C.

G = -196 KJ/MOL -[-305.15 K*0.15] = -242KJ

Thank you.
 
Physics news on Phys.org
Isn't that what I did?
 
You're adding kiloJoules to Joules...
 
dav2008 said:
You're adding kiloJoules to Joules...

No, I think he did not. Because he converted 151 J to 0.15 kJ:

Soaring Crane said:
G = -196 KJ/MOL -[-305.15 K*0.15] = -242KJ
 
PPonte said:
No, I think he did not. Because he converted 151 J to 0.15 kJ:
Oops didn't notice that.