Calculating frequency of the second harmonic

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The fundamental frequency of a violin string is 283 Hz, and the frequency of the second harmonic is calculated by doubling this value, resulting in 566 Hz. The discussion includes the use of relevant equations, such as f(n) = n*v/2L, but the initial calculations led to confusion. Participants clarify that the second harmonic is one octave above the fundamental frequency, which is a musical concept where an octave is defined as doubling the frequency. The final conclusion confirms that the frequency of the second harmonic is indeed 566 Hz. Understanding the relationship between harmonics and octaves is key to solving similar problems.
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Homework Statement


The fundamental frequency of a violin string is 283 Hz. Calculate the frequency of the 2nd harmonic.

Known:
f = 283 Hz

Homework Equations


v = fλ
f(n) = n*v/2L
λ= L
v(sound) = 343 m/s

The Attempt at a Solution


λ = 343/283 = 1.21 m

f(2) = 2*343/2*1.21 = 283 Hz.

I'm getting the same answer as the original problem and I'm not too sure where to go from here. Any help would be much appreciated! Thankyou
 
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You are over-thinking the problem.
The 2'nd harmonic must one octave above the fundamental.
What is an octave in music?
 
Oh I see, so an octave would be twice the frequency? I'm simply just doubling 283Hz to 566Hz
 

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