Calculating Gearbox Torque for Rotating a 500kg Load with a Handwheel Setup

[Rajashekar]

Hi team
In my one of the application I have to use the gear box to rotate 500 kg load
I have to use handwheel to rotate
I am using the formula
Torque= force x per. Distance x coefficient of friction
= 500x.7x.8 : 2800 Nm
Is it correct to calculate the torque
I have attached the image for clarity could you please help

Thanks in advance
Regards
Raj

 

[benny_91]

Hi team
In my one of the application I have to use the gear box to rotate 500 kg load
I have to use handwheel to rotate
I am using the formula
Torque= force x per. Distance x coefficient of friction
= 500x.7x.8 : 2800 Nm
Is it correct to calculate the torque
I have attached the image for clarity could you please help

Thanks in advance
Regards
Raj

Your use of coefficient of friction seems incorrect. Moreover you have mentioned that a hand-wheel would be used for rotation but the figure shows something far different from a hand-wheel setup. If you can sketch the actual setup, take a pic of it and post it then it will be easier to answer your question.

 

[Rajashekar]

Your use of coefficient of friction seems incorrect. Moreover you have mentioned that a hand-wheel would be used for rotation but the figure shows something far different from a hand-wheel setup. If you can sketch the actual setup, take a pic of it and post it then it will be easier to answer your question.

Hi Benny
Thanks for your reply
I have attached the image for your understanding
The gearbox is mounted to a block
The block has a guide rod and that swivels when gearbox is operated
The gearbox is a double reduction gearbox