Calculating Gearbox Torque for Rotating a 500kg Load with a Handwheel Setup

  • Thread starter Thread starter Rajashekar
  • Start date Start date
  • Tags Tags
    Calculation Torque
Click For Summary
SUMMARY

The discussion centers on calculating the torque required to rotate a 500 kg load using a gearbox and a handwheel setup. The user, Raj, applies the formula Torque = Force x Perpendicular Distance x Coefficient of Friction, arriving at a torque value of 2800 Nm. However, forum members point out potential inaccuracies in the application of the coefficient of friction and question the appropriateness of the handwheel setup depicted in the attached image. Clarification on the actual setup is recommended for accurate assistance.

PREREQUISITES
  • Understanding of torque calculations in mechanical systems
  • Familiarity with gearbox types, specifically double reduction gearboxes
  • Knowledge of the coefficient of friction and its application in torque calculations
  • Basic principles of load dynamics and force application
NEXT STEPS
  • Research the correct application of the coefficient of friction in torque calculations
  • Learn about the mechanics of double reduction gearboxes
  • Explore methods for accurately sketching and documenting mechanical setups
  • Investigate alternative methods for calculating torque in various mechanical configurations
USEFUL FOR

Mechanical engineers, students in mechanical design, and anyone involved in the design and analysis of gearbox systems and load handling mechanisms.

Rajashekar
Messages
7
Reaction score
0
Hi team
In my one of the application I have to use the gear box to rotate 500 kg load
I have to use handwheel to rotate
I am using the formula
Torque= force x per. Distance x coefficient of friction
= 500x.7x.8 : 2800 Nm
Is it correct to calculate the torque
I have attached the image for clarity could you please help

Thanks in advance
Regards
Raj
 

Attachments

  • IMG-20160802-WA0005.jpeg
    IMG-20160802-WA0005.jpeg
    33.8 KB · Views: 779
Engineering news on Phys.org
Rajashekar said:
Hi team
In my one of the application I have to use the gear box to rotate 500 kg load
I have to use handwheel to rotate
I am using the formula
Torque= force x per. Distance x coefficient of friction
= 500x.7x.8 : 2800 Nm
Is it correct to calculate the torque
I have attached the image for clarity could you please help

Thanks in advance
Regards
Raj
Your use of coefficient of friction seems incorrect. Moreover you have mentioned that a hand-wheel would be used for rotation but the figure shows something far different from a hand-wheel setup. If you can sketch the actual setup, take a pic of it and post it then it will be easier to answer your question.
 
benny_91 said:
Your use of coefficient of friction seems incorrect. Moreover you have mentioned that a hand-wheel would be used for rotation but the figure shows something far different from a hand-wheel setup. If you can sketch the actual setup, take a pic of it and post it then it will be easier to answer your question.
Hi Benny
Thanks for your reply
I have attached the image for your understanding
The gearbox is mounted to a block
The block has a guide rod and that swivels when gearbox is operated
The gearbox is a double reduction gearbox
 

Attachments

  • P_20160805_092925.jpg
    P_20160805_092925.jpg
    31.5 KB · Views: 640

Similar threads

  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 8 ·
Replies
8
Views
7K
  • · Replies 5 ·
Replies
5
Views
5K
Replies
9
Views
2K
  • · Replies 22 ·
Replies
22
Views
6K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K