Calculating Heat and Work in Thermodynamics of Gas at 100°C and 1.01 x 10^5 pa

[hoyy1kolko]

Homework Statement

At 100°C and pressure of 1.01 x 10^5 pa,1.00kg steam occupies a volume of 1.67m^3.The volume of 1.00kg water is 1.04 x 10^-3 m^3.the specific latent heat of vaporisation of water at 100°C is 2.26 x 10^6 J kg^-1.When 1.00kg water changes into steam at 100°C and pressure of 1.01 x 10^5 pa,calculate

A)heat supplied
B)Work done by the system
C)Increase in internal energy of the system

Homework Equations

P(v2-v1).my book lack of example .So i try a lot of times but can't do it.help me

The Attempt at a Solution

I can't solve the question.The book din have this type of example.

 

[jambaugh]

You should be able to calculate the internal energy of the system for both cases.

You should also be able to calculate the two enthalpies. Recall that enthalpy is the system energy plus the work required to place the system within a given volume of constant pressure fluid. i.e. you must displace something else at that pressure and volume to contain the system, i.e. you must do work on the environment.