Calculating Heat Loss through 1m Glass Pane - 15oC Difference

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To calculate heat loss through a 1m square pane of 6 mm thick glass with a 15°C temperature difference, the thermal conductivity (k) of glass is 0.72 W m^-1 K^-1. The formula used is the rate of heat loss equals k multiplied by the area and the temperature difference divided by the thickness in meters. The thickness of 6 mm is converted to meters as 6 x 10^-3 m, which is essential for the calculation. The confusion arises from converting millimeters to meters, as 6 mm equals 0.006 m. Understanding this conversion is crucial for accurate heat loss calculations.
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Determine the heat loss through a 1m square pane of 6 mm thick glass for a temperature difference of 15oC.
Thermal conductivity of glass is k = 0.72 W m^-1 K^-1
Solution
Rate of loss of heat = 0.72W m^-1 K^-1 x 1 m^2 x 15oC/(6x10^-3 m )
<--- Ok so I understand everything but I don't understand where my teacher gets 6x10^-3 ?? is not in the question that number.

Please help me
 
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luigihs said:

Determine the heat loss through a 1m square pane of 6 mm thick glass for a temperature difference of 15oC.
Thermal conductivity of glass is k = 0.72 W m^-1 K^-1
Solution
Rate of loss of heat = 0.72W m^-1 K^-1 x 1 m^2 x 15oC/(6x10^-3 m )
<--- Ok so I understand everything but I don't understand where my teacher gets 6x10^-3 ?? is not in the question that number.

Please help me

What is 6mm in meters?
 
gneill said:
What is 6mm in meters?

Cheers! I'm so stupid
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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