Calculating Heat Flow in Composite Sheet with Different Thermal Conductivities

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SUMMARY

This discussion focuses on calculating heat flow through a composite sheet made of rubber and cardboard, each 2 mm thick, with thermal conductivities of 0.13 W m-1 K-1 and 0.05 W m-1 K-1, respectively. The outer faces of the composite are maintained at temperatures of 0 °C and 25 °C. The heat conduction equation Q/Time = (Thermal conductivity) x (Area) x (Thot - Tcold)/Thickness is utilized to determine heat flow, but the challenge arises in combining the thermal resistances of the two materials. The solution involves treating each layer as a thermal resistance and applying principles analogous to Ohm's law.

PREREQUISITES
  • Understanding of heat conduction principles
  • Familiarity with thermal conductivity and its units
  • Knowledge of thermal resistance concepts
  • Basic grasp of Ohm's law and its application to thermal systems
NEXT STEPS
  • Study the concept of thermal resistance in series and parallel configurations
  • Learn how to apply the heat conduction equation in composite materials
  • Explore the relationship between thermal conductivity and thermal resistance
  • Investigate practical applications of heat transfer calculations in engineering
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This discussion is beneficial for students and professionals in thermal engineering, materials science, and anyone involved in heat transfer analysis, particularly those working with composite materials.

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1. A sheet of rubber and a sheet of cardboard, each 2 mm thick, are pressed together and their outer faces are maintained respectively at 0 oC and 25 oC. If the thermal conductivities of rubber and cardboard are respectively 0.13 and 0.05 W m-1 K-1, find the quantity of heat which flows in one hour across a piece of the composite sheet of area 100 cm2. 2. I know how to solve the problem when a single object with one thermal conductivity is give, But how do I solve a problem with two different objects with two different thermal conductivities?3. I used the equation Heat conduction Q/ Time = (Thermal conductivity) x (Area) x (Thot -Tcold)/Thickness to find the Heat which flows in the rubber and the cardboard separately but after that I was at a lost.

Please help me solve it. An explanation would be nice if possible because I don't really care about the answer I just want to know how to do it.
Thanks in Advance :)
 
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Each of the layers can also be seen as a thermal resistance (which is the inverse value of the conductivity). Accoring to Ohm's law (which is much more common: U = R⋅I), you can also establish the same formula for heat transfer/conduction: ΔT = RTh ⋅ Q. You can find the (total) resistance of thermal resistances in series and parallel like it is done with electrical resistances/impedances. It#s up to you if you transform the gained RTh back into a conductivity and use Q = K ⋅ ΔT or Q = ΔT / RTh ⋅A. Just be careful with the dimenions of K and RTh, but as you know the formula, the adaption should be easy.
 

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