How Does Thermal Conductivity Affect Heat Transfer Between Two Water Vessels?

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SUMMARY

This discussion focuses on the thermal conductivity of a metal rod and its effect on heat transfer between two adiabatic water vessels. The problem involves calculating the time taken for the temperature difference to reduce to half its initial value using the formula MS(dT/dt) = KA(ΔT/L). Key parameters include the mass of water (M), specific heat capacity (S), thermal conductivity (K), length of the rod (L), and cross-sectional area (A). The conversation emphasizes the importance of accurately connecting temperature differences to heat flow and the resulting changes in temperature.

PREREQUISITES
  • Understanding of thermal conductivity and its role in heat transfer.
  • Familiarity with the concepts of adiabatic processes and specific heat capacity.
  • Knowledge of differential equations as applied to heat transfer problems.
  • Basic principles of thermodynamics, particularly regarding heat flow.
NEXT STEPS
  • Study the derivation of the heat transfer equation for conductive materials.
  • Learn about the implications of adiabatic processes in thermodynamics.
  • Explore numerical methods for solving differential equations in heat transfer scenarios.
  • Investigate the impact of varying thermal conductivities on heat transfer rates in different materials.
USEFUL FOR

This discussion is beneficial for physics students, engineers specializing in thermal systems, and professionals involved in heat transfer analysis and design.

Roxas ross
1. Two adibatic vessels,each of mass (M) of water at different temperatures.the ends of a metal rod of length (L),area of cross section (A) and thermal conductivity (K),are inserted in the vessels filled with water.there are no openings on these vessels other than the place where the ends of the rod meet the vessels.find the time taken for the temperature difference to become half its initial value.the specific heat capacity of water is (S). neglect the heat capacity of the rod and the container and any loss of heat to the atmosphere.2. MS(dT/dt)=rate of heat flow
KA( temperature difference between the ends of the rod/length of rod)= rate of heat flow through the rod.
3.net rate of heat that flows across the rod = rate of heat dissipated by the vessel at higher temperature( at an instant) - rate of heat absorbed by the vessel with lower temperature ( at the same instant)
 
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Roxas ross said:
net rate of heat that flows across the rod = rate of heat dissipated by the vessel at higher temperature( at an instant) - rate of heat absorbed by the vessel with lower temperature ( at the same instant)
That contradicts the correct statement you made at point 2 re heat flow.

Please show a real attempt.
You need to connect temperature difference to resulting heat flow, as you have, but then connect that heat flow with the resulting change in temperature difference.

In future, please use a title that gives some clue as to the subject matter.
 
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