The discussion focuses on calculating the heat required to raise the temperature of 90g of water from 15.5°C to 85°C using the formula QH2O = mH2O * cH2O * ΔTH2O. The specific heat of water is established as 1 cal/g°C. The total heat required is calculated by determining the temperature change (ΔTH2O) and applying the mass and specific heat values. Additionally, the impact of the aluminum vessel's mass (178g) on the overall heat calculation is raised as a consideration.
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kimkibun said:Homework Statement
An aluminum vessel hose mass is 178g contains 90g of water at 15.5°C. How many calories of heat are required to bring the water to a final temperature of 85°C? The specific heat of water is 1cal/g°C.
Given:
mAl=178g
mH2O=90g
T1=15.5°C
T2=85°C
cH2O=1cal/g°C
Homework Equations
Im planning to use this formula for heat quantity
QH2O=mH2OcH2OΔTH2O
The Attempt at a Solution