Calculating Height of Racket Ball Leaving Racket

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To calculate the height of the racket ball when it left the racket, the horizontal distance of 1.97 m and the speed of 4.81 m/s were used to determine the time of flight, resulting in approximately 0.41 seconds. The next step involves using the formula for vertical motion, y = (1/2)gt^2, to calculate the height. By substituting the time into the equation, the height can be accurately determined. This approach effectively combines horizontal and vertical motion principles. The calculations confirm that the method is valid for finding the initial height of the racket ball.
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A racket ball is struck in such a way that it leaves the racket with a speed of 4.81 m/s in the horizontal direction. When the ball hits the court, it is a horizontal distance of 1.97 m from the racket.
Find the height of the racket ball when it left the racket.

okay so what I did was try to find the time so I did x=VoT which is 1.97=4.81t and I got t=.40956... I think I am on the right path so to find height now can I just do y=gt^2/2 to get my height?
 
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That should work.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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