Calculating Horizontal Speed of a Stealth Bomber

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SUMMARY

The discussion focuses on calculating the horizontal speed of a stealth bomber that drops a bomb from a height of 3500 meters, which travels a horizontal distance of 1.25 kilometers. The relevant kinematic equations for projectile motion are essential for solving this problem. Additionally, a secondary scenario involves a brick thrown at a 25-degree angle with an initial speed of 15 m/s, which remains in flight for 3.0 seconds, prompting a calculation of the building's height. Both scenarios require a solid understanding of kinematic equations to derive the necessary answers.

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  • Kinematic equations for projectile motion
  • Basic principles of horizontal and vertical motion
  • Trigonometry for angle calculations
  • Understanding of initial velocity and time of flight
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  • Study the kinematic equations for projectile motion
  • Learn how to calculate horizontal and vertical components of motion
  • Explore the effects of angle on projectile trajectories
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Students in physics, educators teaching kinematics, and anyone interested in understanding projectile motion and its applications in real-world scenarios.

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a stealth bomber on a training mission drops one of its bombs from a height of 3500m during level flight. The bomb travels a horizontal distance of 1.25 km. What was the plane's horizontal speed?



a brick is thrown upward from the top of a building at an angle of 25 degrees to the horizontal and with an initial speed of 15 m/s. it strikes the ground below. if the brick is in flight for 3.0 s, how tall is the building?


i don't know the equation or the answer, can someone provide both for me?
 
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read the rules about homework questions and try again.

hint: the projectile motion equations are usually found under kinematic equations or just kinematics.
 

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