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Parabolic motion problem: bomber plane case

  1. Sep 24, 2014 #1
    • Warning! Posting template must be used for homework questions.
    Ok guys, I got this problem but I don't know how to solve it properly. The problem is about parabolic motion and it says:

    A plummeting bomber plane that makes an angle of 53° with the positive y-axis throws a bomb down with a height of 730 m. The bomb impacts the ground 5 s later. a) What was the bomber speed? b) How much distance in the x-axis does the bomb cover in the air? c) What are the components of the velocity just when the bomb hits the ground?

    Well before writing down the formulas, I want to say that I got confused because I don't know what kind of motion this is, if it is projectile motion or horizontal projection since we have an angle for the initial velocity. The formulas are most likely to be:

    [itex]R_x=\frac{v_{0}^{2}(\mathbf{sin}2\theta)}{g}[/itex]
    [itex]y_{max}=\frac{v_{0}^{2}(\mathbf{sin}^2\theta)}{2g}[/itex]
    [itex]\Delta t_f=\frac{2v_0(\mathbf{sin}\theta)}{g}[/itex]
    [itex]v_x=\left | \mathbf{v} \right |\mathbf{cos}\theta[/itex]
    [itex]v_y=\left | \mathbf{v} \right |\mathbf{sin}\theta[/itex]


    I attempted to reach the solutions, however; I'm stuck that I need more data like the initial velocity magnitude as well as the final velocity's so I'm not able to find the time and I cannot find the distance, help please.
     
  2. jcsd
  3. Sep 24, 2014 #2

    mfb

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    It is a general motion of an object in free fall.
    You can focus on the vertical direction first. An object with an initial height of 730m and an unknown velocity hits the ground 5 seconds later. What was its vertical velocity?
     
  4. Sep 24, 2014 #3
    That's what I want to find :\
     
  5. Sep 24, 2014 #4

    mfb

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    Then you should find a formula for the distance traveled as function of the other variables, right?

    I will not give you a solution - it is your homework. I can give hints, but you should try to figure it out yourself.
     
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