Calculating Hurricane Distance with Vectors

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SUMMARY

The discussion focuses on calculating the distance of a hurricane from Grand Bahama Island after it changes direction and speed. Initially, the hurricane moves 60.0 degrees north of west at 41.0 km/h for 3 hours, followed by a shift to due north at 25.0 km/h for 1.5 hours. The total distance from Grand Bahama can be determined using vector addition and the formula v=d/t. Participants emphasize the importance of visualizing the problem through vector diagrams to accurately calculate the final position of the hurricane.

PREREQUISITES
  • Understanding of basic physics concepts, particularly velocity and distance calculations.
  • Familiarity with vector addition and graphical representation of vectors.
  • Knowledge of trigonometry, specifically angles and their application in vector problems.
  • Ability to interpret and create diagrams to visualize motion and direction.
NEXT STEPS
  • Learn how to perform vector addition in physics problems.
  • Study the application of trigonometric functions in calculating distances and angles.
  • Explore graphical methods for solving physics problems, including drawing vector diagrams.
  • Investigate the effects of changing speeds and directions on the trajectory of moving objects.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding motion dynamics, particularly in the context of meteorological phenomena like hurricanes.

Maddy315
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The eye of a hurricane passes over Grand Bahama Island in a direction 60.0 degrees north of west with a speed of 41.0km/h. Three hours later, the course of the hurricane suddenly shifts due north, and its speed slows to 25.0 km/h. How far from Grand Bahama is the hurricane 4.5 h after it passes over the island?

I know we're going over v=d/t but my teacher didn't have time to fully explain.
I'm completely confused and I'm not so sure that my picture came out right either. Help?

b]
 
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Maddy315 said:
The eye of a hurricane passes over Grand Bahama Island in a direction 60.0 degrees north of west with a speed of 41.0km/h. Three hours later, the course of the hurricane suddenly shifts due north, and its speed slows to 25.0 km/h. How far from Grand Bahama is the hurricane 4.5 h after it passes over the island?

I know we're going over v=d/t but my teacher didn't have time to fully explain.
I'm completely confused and I'm not so sure that my picture came out right either. Help?

b]

SO what did you calculate, and at least describe your picture - [like the first arrow is like a clock hand pointing to 9:00, then one from there pointing at 6:00 but hopefully not either of those directions]
 
Like everything else in life, the best way to do it is through vectors.

And graphicall would be the best way to see it, so start by drawing a line going in the first direction, and then a line going in the second starting from the tip of the first.

The line between the tip of the second and the start will be your answer, graphically.
 

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