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**Calculating "Hybrid Probability" When Two Probabilities Affect the Same Event**

In this "minesweeper grid:"

http://a1.sphotos.ak.fbcdn.net/hphotos-ak-snc7/401541_958641223250_10904138_40885678_1330475914_n.jpg [Broken]

...I can calculate the probability of the square with the question mark being a mine at 2 in 3 using just the box numbered "3," or 1 in 2 using just the box numbered "4."

It seems to me that knowing this, I should be able to calculate a "hybrid" probability that is somewhere between 0.5 and 0.67. Any ideas on how I can do this, or what one would even call such a calculation?

Thanks!!

--Jon

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