Calculating Hybridisation and Existence of a Compound with Boron

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Homework Statement
The question asked the hybridisation and shape of ##BO_3^-##
Relevant Equations
N=##(X+Y-C+A)/2##
where C is positive charge on the compound
A is negative charge on the compound
X is valence electrons of central atom
Y is no. of univalent side atoms.
If N=2,then sp.
One would easily calculate its hybridisation by the above formula which comes out to be sp.
But my doubt is that will the compound even exist?As boron will become electron deficient and how we will calculate no. of bond pairs and lone pairs.Please clear my doubt.
 
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Physics lover said:
One would easily calculate its hybridisation by the above formula which comes out to be sp.
But my doubt is that will the compound even exist?As boron will become electron deficient and how we will calculate no. of bond pairs and lone pairs.Please clear my doubt.

Have you tried to draw the lewis structure??
 
Javier0289 said:
Have you tried to draw the lewis structure??
yes not able to draw it,that's why i asked here.
 
Physics lover said:
yes not able to draw it,that's why i asked here.
If your doubt is only the existence, there's sodium perborate. Check your notes and the formula because there isn't a sp Boron in the lewis structure of such compound
 
Javier0289 said:
If your doubt is only the existence, there's sodium perborate. Check your notes and the formula because there isn't a sp Boron in the lewis structure of such compound
Thanks i got it.It's ##sp^2## hybridised and i think it is planar too isn't it?
 
Physics lover said:
Thanks i got it.It's ##sp^2## hybridised and i think it is planar too isn't it?
I don't think is planar, the boron has more character $$sp^3$$... nevertheless you can check it out with the lewis structure in the internet and do an analysis (bond order, paired and unpaired electrons, etc)
 
Physics lover said:
Homework Statement: The question asked the hybridisation and shape of ##BO_3^-##

I don't think BO3- exists or if it does, it is not a very common species. [BO3]3- does exist, however. Perhaps you can clarify with your instructor if BO3- is the correct formula.
 
Ha ha! Formula for perborate this is...
Chemical formula is not the same as empirical formula. Tricksy, tricksy!