Calculating Impact of 150kg Dropped onto 1,200kg Pile

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SUMMARY

The discussion focuses on calculating the impact of a 150 kg mass dropped from a height of 2.5 meters onto a 1,200 kg pile, which drives the pile 7 cm into the ground. The initial velocity of the pile and the driving weight immediately after impact is calculated using the formula V = √(2 * g * h), resulting in approximately 7.004 m/s. The average resisting force exerted by the ground is determined using Newton's second law, yielding a force of 1471.68 N. Participants emphasize the importance of showing all work and relevant equations for accurate verification of calculations.

PREREQUISITES
  • Understanding of kinematic equations, specifically V = √(2 * g * h)
  • Familiarity with Newton's second law (F = MA)
  • Basic knowledge of gravitational acceleration (g = 9.81 m/s²)
  • Concept of energy transfer during impact
NEXT STEPS
  • Research the derivation and application of kinematic equations in impact scenarios
  • Study the principles of energy conservation in collisions
  • Learn about dynamic force calculations and their implications in engineering
  • Explore advanced topics in impact mechanics and material deformation
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Students in physics or engineering, educators teaching mechanics, and professionals involved in impact analysis or material science will benefit from this discussion.

JamesTheEng
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Homework Statement


A mass of 150 KG is dropped onto a pile of mass 1,200 kg from a height of 2.5m and drives it 7cm into the ground. calculate (a) the initial veocity of pile and driving weight immediately after impact, (b) the average resisting force excerted by the ground.


Homework Equations


Not sure Please help.


The Attempt at a Solution


None worth writing please post a soloution and a step by step guide on how to solve the problem.
 
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JamesTheEng: You must list relevant equations yourself, and show your valid work; and then someone might check your math. We are not allowed to provide answers here. We can only check your math, after you do all of the work.
 


ok thank you, here is my attempt not fully done but could you let me know if I am on the right track?..
1st i apply this formula to find the velocity
V= Squareroot (2xGravityxheight) = 7.004

Then i put in the knowns i have into the equation V²=U²+2as to find accelleration

7.004²=0²+(2x(a)x(2.5)) i transpose and come to 9.8112

I then Apply Newtons 2nd law F=MA

9.8112x150= 1471.68N

Am i on the right track please message back.
 

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