Calculating Impulse Based off a graph

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The discussion revolves around calculating impulse from a force graph for a 3.0 kg particle. The initial attempt involved summing the areas under the force curve but resulted in an incorrect value of 5000 N s. Participants noted that the error might stem from a misunderstanding of units, specifically confusing seconds with milliseconds. This realization led to a correction in the approach to calculating impulse. The conversation emphasizes the importance of unit consistency in physics calculations.
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Homework Statement



What is the impulse on a 3.0 particle that experiences the force shown in the figure (Figure 1) ?
Figure 1:
http://session.masteringphysics.com/problemAsset/1382988/2/09.EX04.jpg


Homework Equations


Impulse equations, force equations, how they relate.


The Attempt at a Solution


I added the area above the x-axis for the time interval 2 to 8 and subtracted the areas from 0 to 2 and 8 to 10. This answer came out to be 5000 N s which is incorrect. I'm confused because I thought the integral of force (the area bounded by the force graph) is equal to impulse.

Help would be greatly appreciated. :smile:
 
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Your result seems too large. s vs ms, perhaps?
 
lewando said:
Your result seems too large. s vs ms, perhaps?

Yes! I can't believe I didn't think of that. Thank you!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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