Calculating Impulse Based off a graph

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SUMMARY

The discussion centers on calculating impulse from a force-time graph for a 3.0 kg particle. The participant initially calculated the impulse as 5000 N·s but later realized the error stemmed from a misunderstanding of time units, specifically confusing seconds with milliseconds. The correct approach involves integrating the area under the force graph, which directly correlates to impulse. This highlights the importance of unit consistency in physics calculations.

PREREQUISITES
  • Understanding of impulse and momentum concepts
  • Familiarity with force-time graphs
  • Knowledge of integration techniques in physics
  • Basic skills in unit conversion (seconds to milliseconds)
NEXT STEPS
  • Review the principles of impulse and momentum in classical mechanics
  • Learn how to calculate the area under a curve using integration
  • Study unit conversion techniques, particularly in physics contexts
  • Explore examples of force-time graphs and their applications in impulse calculations
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Students in physics courses, educators teaching mechanics, and anyone looking to improve their understanding of impulse calculations and graph interpretation.

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Homework Statement



What is the impulse on a 3.0 particle that experiences the force shown in the figure (Figure 1) ?
Figure 1:
http://session.masteringphysics.com/problemAsset/1382988/2/09.EX04.jpg


Homework Equations


Impulse equations, force equations, how they relate.


The Attempt at a Solution


I added the area above the x-axis for the time interval 2 to 8 and subtracted the areas from 0 to 2 and 8 to 10. This answer came out to be 5000 N s which is incorrect. I'm confused because I thought the integral of force (the area bounded by the force graph) is equal to impulse.

Help would be greatly appreciated. :smile:
 
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Your result seems too large. s vs ms, perhaps?
 
lewando said:
Your result seems too large. s vs ms, perhaps?

Yes! I can't believe I didn't think of that. Thank you!
 

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