Calculating Initial Speed and Velocity of Thrown Keys

  • Thread starter Thread starter cbrowne
  • Start date Start date
  • Tags Tags
    Speed
Click For Summary
SUMMARY

The discussion focuses on calculating the initial speed and final velocity of keys thrown vertically upward. The initial speed (Vi) is determined to be 10.016 m/s, while the final velocity (Vf) just before the keys are caught is -4.684 m/s. The calculations utilize the equations of motion, specifically Δd = ViΔt + 1/2 aΔt and Vf = Vi + at, with gravitational acceleration (g) set at -9.8 m/s². The problem is framed within a real-world scenario involving a man throwing keys to his wife, emphasizing practical application of kinematic equations.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of gravitational acceleration (g = -9.8 m/s²)
  • Ability to manipulate algebraic equations
  • Familiarity with basic concepts of velocity and displacement
NEXT STEPS
  • Study the derivation of kinematic equations for vertical motion
  • Explore the concept of free fall and its implications on velocity
  • Learn about projectile motion and its applications
  • Practice solving similar problems involving vertical throws and motion
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of motion, particularly in vertical trajectories and kinematic calculations.

cbrowne
Messages
30
Reaction score
0

Homework Statement



A man standing on the sidewalk throws a set of keys vertically upward to his
wife in the window of their apartment 4.0 m above. The wife catches the keys
1.5 s later. (a) With what initial speed were the keys thrown? (b) What is the
velocity of the keys just before they were caught? (c) Draw a diagram showing
the trajectory of the keys.



The Attempt at a Solution




d= 4.0 m
Δt= 1.5 s
g= -9.8 m/s^2

Δd= ViΔt+1/2aΔt

-ViΔt= 1/2 at2-Δd

-Vi= 1/2 at2- Δd /Δt

-Vi= -10.016 m/s

ANSWER FOR A ->>Vi= 10.016 m/s

b) Vf= Vi+at

Vf= (110.016 m/s)-(9.8)(1.5)= (-4.684m/s)

ANSWER FOR B >> -4.684 m/s
 
Physics news on Phys.org
Hi cbrowne,

cbrowne said:

Homework Statement



A man standing on the sidewalk throws a set of keys vertically upward to his
wife in the window of their apartment 4.0 m above. The wife catches the keys
1.5 s later. (a) With what initial speed were the keys thrown? (b) What is the
velocity of the keys just before they were caught? (c) Draw a diagram showing
the trajectory of the keys.



The Attempt at a Solution




d= 4.0 m
Δt= 1.5 s
g= -9.8 m/s^2

Δd= ViΔt+1/2aΔt

-ViΔt= 1/2 at2-Δd

-Vi= 1/2 at2- Δd /Δt

-Vi= -10.016 m/s

ANSWER FOR A ->>Vi= 10.016 m/s

b) Vf= Vi+at

Vf= (110.016 m/s)-(9.8)(1.5)= (-4.684m/s)

ANSWER FOR B >> -4.684 m/s


Your answers look right to me.
 
Your answers are correct.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 22 ·
Replies
22
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
8
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
2K