Calculating Initial Velocity of Projectile Motion Without Time Information

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Homework Help Overview

The discussion revolves around calculating the initial velocity of a projectile launched at a 45-degree angle from a height of 1 meter, which lands 2.5 meters away at a height of 0 meters. A secondary scenario involves a massless ball that bounces before reaching its final landing spot, with an initial angle of -45 degrees. Participants explore whether these calculations can be made without knowing the time of flight.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the feasibility of calculating initial velocity without time information and consider the implications of the ball being massless. There are questions about the nature of the bounce and the assumptions regarding the ball's mass and behavior during the collision.

Discussion Status

The conversation is ongoing, with various participants offering insights and questioning the assumptions made in the problem. Some suggest using energy conservation principles, while others express confusion about the setup and the variables involved. There is no explicit consensus on the best approach, but several lines of reasoning are being explored.

Contextual Notes

Participants note potential typos in the problem statement regarding the mass of the projectile and the angles involved. There is also a recognition that the problem may require simultaneous equations to solve for the unknowns, particularly the point of bounce and the initial velocity.

  • #31
Your formula for y is wrong. It should be
yf = yi + vt - 1/2*g*t^2.
 
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  • #32
rl.bhat said:
Your formula for y is wrong. It should be
yf = yi + vt - 1/2*g*t^2.

I let g=-9.8m/s^2 in my calculations.
 
  • #33
In the equation what is the value of yi?
After the bounce it should be zero. Take it zero and calculated the time.
 
  • #34
physicskid69 said:
I now use that velocity with yf=yi+vt+1/2gt^2 to solve for t where yf=0.1m and yi=0m. This gives me t=0.881s.

Isn't that what I already did?
 
  • #35
Yes. I didn't notice.
0.1 = 4.43*t - 4.9*t^2
Or 4.9*t^2 - 4.43*t + 0.1 = 0
When I solved it I got different answer. Check it.
 
  • #36
rl.bhat said:
Yes. I didn't notice.
0.1 = 4.43*t - 4.9*t^2
Or 4.9*t^2 - 4.43*t + 0.1 = 0
When I solved it I got different answer. Check it.

I get t=0.023s or t=0.881s and since I want the time for when the ball is coming back down I use t=0.881s I believe.
 
  • #37
OK.Then your answer is correct.
 
  • #38
Okay, thank you to everyone that helped out with this.
 
  • #39
Wait a minute. There is one flaw in your solution.
According to you the total time of flight is 1.333 s.
During that time the vertical displacement is 8.7 m!
How is that? .
 
  • #40
That's assuming the ball is falling the entire time and not considering the bounce.
 
  • #41
You have taken two time intervals to calculate the time of flight, taking into account the bounce.
But the vertical space in only 1m!
 
  • #42
rl.bhat said:
You have taken two time intervals to calculate the time of flight, taking into account the bounce.
But the vertical space in only 1m!

Yes I know, the ball falls 1m then bounces back up 1m and finally lands after traveling another 0.9m. This takes a total time of 1.333s.
 
  • #43
OK. Then it is alright.
 

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