# Calculating instantaneous acceleration

1. Jul 30, 2013

1. The problem statement, all variables and given/known data

The position of a particle moving along the x axis is given in centimeters by x = 9.75 + 1.50t3, where t is in seconds

Calculate the instantaneous acceleration at 2.00 s.

2. Relevant equations
x = 9.75 + 1.50t3

I don't understand how i would solve for the acceleration using an equation for distance
i understand Vf=Vo+at and that the instantaneous velocity at this time is .217 m/s

i had to teach myself how to do this so i am not sure i found the velocity correctly

Last edited: Jul 30, 2013
2. Jul 30, 2013

### Staff: Mentor

The way this works in PF is that you are supposed to make an attempt to solve the problem first, and show us what you did so far. Then, if necessary, we can try to get you pointed in the right direction.

Chet

3. Jul 30, 2013

Thanks for the info

4. Jul 30, 2013

### Bandarigoda

You need to derive it. By t subject, do it twice. One derive tell you velocity, second tell you acceleration.

5. Jul 30, 2013

### Clever-Name

How did you arrive at v(2.00s) = 0.217 m/s? Are you familiar with what the derivative of position means?

6. Jul 30, 2013

how would i derive it the second time

7. Jul 30, 2013

### Clever-Name

You have a function for position with respect to time. Take the first time derivative. Show us what you get and what does this new function represent?

8. Jul 30, 2013

### Bandarigoda

Did u ask it from me? I cant understand, sorry my bad english. Am i wrong about the derivation?

9. Jul 30, 2013

### Clever-Name

No, sorry, that was directed at maxalador.

10. Jul 30, 2013

### Bandarigoda

Oh okay. :)

11. Jul 30, 2013