# Calculating instantaneous acceleration

## Homework Statement

The position of a particle moving along the x axis is given in centimeters by x = 9.75 + 1.50t3, where t is in seconds

Calculate the instantaneous acceleration at 2.00 s.

## Homework Equations

x = 9.75 + 1.50t3

I don't understand how i would solve for the acceleration using an equation for distance
i understand Vf=Vo+at and that the instantaneous velocity at this time is .217 m/s

i had to teach myself how to do this so i am not sure i found the velocity correctly

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Chestermiller
Mentor
The way this works in PF is that you are supposed to make an attempt to solve the problem first, and show us what you did so far. Then, if necessary, we can try to get you pointed in the right direction.

Chet

The way this works in PF is that you are supposed to make an attempt to solve the problem first, and show us what you did so far. Then, if necessary, we can try to get you pointed in the right direction.

Chet
Thanks for the info

You need to derive it. By t subject, do it twice. One derive tell you velocity, second tell you acceleration.

How did you arrive at v(2.00s) = 0.217 m/s? Are you familiar with what the derivative of position means?

You need to derive it. By t subject, do it twice. One derive tell you velocity, second tell you acceleration.
how would i derive it the second time

how would i derive it the second time
You have a function for position with respect to time. Take the first time derivative. Show us what you get and what does this new function represent?

How did you arrive at v(2.00s) = 0.217 m/s? Are you familiar with what the derivative of position means?
Did u ask it from me? I cant understand, sorry my bad english. Am i wrong about the derivation?

Did u ask it from me? I cant understand, sorry my bad english. Am i wrong about the derivation?
No, sorry, that was directed at maxalador.

No, sorry, that was directed at maxalador.
Oh okay. :)

sorry guys it turns out that the reason i didnt understand was because i was doing it wrong. thanks for all your help though