The position of a particle moving along the x axis is given in centimeters by x = 9.75 + 1.50t3, where t is in seconds
Calculate the instantaneous acceleration at 2.00 s.
x = 9.75 + 1.50t3
I don't understand how i would solve for the acceleration using an equation for distance
i understand Vf=Vo+at and that the instantaneous velocity at this time is .217 m/s
i had to teach myself how to do this so i am not sure i found the velocity correctly